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If blocks are associated with different tasks or conditions to be classified, the schedule vector, '''''schedule''''' can be created similarly, but with some modification. Here's some examples. | If blocks are associated with different tasks or conditions to be classified, the schedule vector, '''''schedule''''' can be created similarly, but with some modification. Here's some examples. | ||
sample_rate=2.047; %each sample spans 2.047 seconds in this fMRI example | |||
t=cell2mat({expinfo.data.timestamp}); | t=cell2mat({expinfo.data.timestamp}); | ||
vols=floor(t/ | vols=floor(t/sample_rate)+1; %convert the timestamps into volume numbers | ||
cond=double(cell2mat({expinfo.data.conditon})); %what condition is each trial? | cond=double(cell2mat({expinfo.data.conditon})); %what condition is each trial? | ||
%p.s., note the typo on "conditon" | %p.s., note the typo on '''"conditon"''' | ||
b=double(cell2mat({expinfo.data.block})); %what block is each trial? | b=double(cell2mat({expinfo.data.block})); %what block is each trial? | ||
bnums=unique(b); %what are the different blocks? | bnums=unique(b); %what are the different blocks? |
Revision as of 13:43, 13 July 2016
Determine Targets
Classifying Task vs Baseline Blocks
If the goal is simply to distinguish task block from rest periods, use findBlockBoundaries
as follows:
sample_rate=2.047; %an fMRI study, with a TR=2.047 seconds b=findBlockBoundaries([], sample_rate); schedule=zeros(1,b(end)); %1 zero for each volume -- default=baseline for block=1:size(b,1) schedule(b(block,1):b(block,2))=1; %block volumes get a '1' end
Classifying Task Blocks
If blocks are associated with different tasks or conditions to be classified, the schedule vector, schedule can be created similarly, but with some modification. Here's some examples.
sample_rate=2.047; %each sample spans 2.047 seconds in this fMRI example t=cell2mat({expinfo.data.timestamp}); vols=floor(t/sample_rate)+1; %convert the timestamps into volume numbers cond=double(cell2mat({expinfo.data.conditon})); %what condition is each trial? %p.s., note the typo on "conditon" b=double(cell2mat({expinfo.data.block})); %what block is each trial? bnums=unique(b); %what are the different blocks? lookup=[0,1;0,2]; %condition codes that make up each block condition bcodes=[1,2];%code assigned to each block condition schedule=zeros(1,vols(end));%blank schedule preallocated for each volume %%This loop will iterate through all the numbered blocks and use the lookup %%table to determine which block code to assign each block, depending on %%the individual trial conditions present in that block. %%Then, all individual volumes that belong to that block will get assigned %%that condition code. Anything not assigned a block code will remain '0' %%(or 'rest'/'baseline') for i=1:length(bnums) idx=find(b==bnums(i));%get indices of current block codes=unique(cond(idx));%what conditions are represented in this block? blockcondition=bcodes(ismember(lookup, codes, 'rows'));%lookup the blockcode (in bcodes) that matches the conditions in this block firstvol=vols(idx(1)); lastvol=vols(idx(end)); schedule(firstvol:lastvol)=blockcondition; end
Match Targets to Inputs
Input values will come from time series data, imported and scaled as described here. If any volumes have been discarded from the input time series, the same volumes will need to be deleted from the schedule of targets. Assuming we have a schedule and a set of inputs for a single run, we need to match each input vector to the corresponding condition in the schedule vector. This will use a Matlab function.